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Reduction of copper (II) oxide

The reduction of copper (II) oxide (black) to copper (brown) using hydrogen gas is an example of a redox reaction.
CuO(s) + H2(g) → Cu(s) + H2O(g)
 
a) There is a loss of oxygen for copper (II) oxide, so it is reduced to copper.
b) The oxidation number / state of copper (II)  is +2 and it has been reduced to 0 (for copper metal).
c) The partial / ionic equation for the change is copper (II) ions is
2e- + Cu2+ → Cu
    where a gain of electrons takes places.

d) There is gain of oxygen for hydrogen so it is oxidised.


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Penurunan kuprum (II) oksida

Penurunan kuprum (II) oksida (hitam) kepada kuprum (perang) menggunakan gas hidrogen merupakan contoh tindak balas redoks.
CuO(s) + H2(g) → Cu(s) + H2O(g)

a) Terdapat kehilangan oksigen bagi ion kuprum (II) oksida, justeru ia diturunkan kepada kuprum.
b) Nombor pengoksidaan ion kuprum (II)  ialah +2 dan diturunkan kepada 0 (untuk atom kuprum).
c) Persamaan separa bagi ion kuprum ialah
2e- + Cu2+ → Cu
    di mana terdapat penerimaan elektrons.

d) Hidrogen menerima oksigen dan dioksidakan.
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